A) \[\frac{5R}{12}\]
B) \[\frac{7R}{12}\]
C) \[\frac{3R}{12}\]
D) \[\frac{R}{12}\]
Correct Answer: A
Solution :
Resistances R, R and \[\frac{R}{2}\] are in series, the resultant resistance, \[R'=R+R+\frac{R}{2}=\frac{5R}{2}\] Resistances R' and \[\frac{R}{2}\] are in parallel. Their resultant resistance \[\frac{1}{R}=\frac{2}{5R}+\frac{2}{R}=\frac{2+10}{5R}\] \[R=\frac{5R}{12}\]You need to login to perform this action.
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