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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    \[{{N}_{2}}{{O}_{4}}\rightleftharpoons 2N{{O}_{2}}-Q\] The unit of \[{{K}_{p}}\] for the given reaction is

    A)  atmosphere      

    B)  \[atmospher{{e}^{2}}\]

    C)  \[atmospher{{e}^{-1}}\]

    D)  None of these

    Correct Answer: A

    Solution :

    \[{{N}_{2}}{{O}_{4}}2N{{O}_{2}}-Q\] Applying law of mass action,                 \[{{K}_{P}}=\frac{{{(pN{{O}_{2}})}^{2}}}{P({{N}_{2}}{{O}_{4}})}\]                 \[{{K}_{P}}=\frac{{{(atmosphere)}^{2}}}{atmosphere}\] \[\therefore \] Unit of \[{{K}_{P}}\] is atmosphere.


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