A) ethylamine
B) methylamine
C) dimethylamine
D) trimethylamine
Correct Answer: C
Solution :
Reduction of alkyl isocyanide give secondary amine\[\underset{\begin{smallmatrix} methyl \\ isocyanide \end{smallmatrix}}{\mathop{C{{H}_{3}}-NC}}\,\xrightarrow[4[H]]{Na/{{C}_{2}}{{H}_{5}}OH}\underset{\dimethyl\,\text{amine}}{\mathop{C{{H}_{3}}-\overset{C{{H}_{3}}}{\mathop{\overset{|}{\mathop{N}}\,}}\,-H}}\,\]
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