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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    A body moves a distance of 10 m along a straight line under the action of a force of 5 N. If the work done is 25 J the angle which the force makes with the direction of motion of the body is

    A) \[0{}^\circ \]

    B) \[30{}^\circ \]

    C) \[60{}^\circ \]

    D) \[90{}^\circ \]

    Correct Answer: C

    Solution :

    Given, \[s=10m,\]  \[F=5N,\]   \[W=25J,\] \[\theta =?\] Work done, \[W=Fs\,\cos \theta \] \[\therefore \]  \[\cos \theta =\frac{W}{Fs}=\frac{25}{5\times 10}=\frac{1}{2}\]                 \[=\cos \,{{60}^{o}}\] \[\therefore \]  \[\theta ={{60}^{o}}\]


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