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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    A telescope, consisting of an objective of focal length 60 cm and a single eye lens of focal length 5 cm is focussed on a distant object is such a way that parallel rays comes out from the eye lens. If the object subtends an angle \[2{}^\circ \] at the objective the angle subtended by the image at the eye is

    A) \[10{}^\circ \]

    B) \[24{}^\circ \]

    C) \[50{}^\circ \]

    D) \[1/6{}^\circ \]

    Correct Answer: B

    Solution :

    Given,  \[{{f}_{0}}=60cm,\] \[{{f}_{e}}=5cm\] Visual angle \[(\alpha )={{2}^{o}}\] Visual angle   \[(\beta )=?\] Magnifying power of a telescope \[(M)=\frac{{{f}_{o}}}{{{f}_{e}}}=\frac{\beta }{\alpha }\]                 \[\therefore \]  \[\beta =\alpha \frac{{{f}_{o}}}{{{f}_{e}}}={{2}^{o}}\times \frac{60}{5}={{24}^{o}}\]


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