2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    Radius of a capillary is \[2\times {{10}^{-3}}m.\text{ }A\] liquid of weight \[6.28\times {{10}^{-4}}N\] may remain in the capillary, then the surface tension of liquid will be

    A)  \[5\times {{10}^{-3}}N/m\]       

    B)  \[5\times {{10}^{-2}}N/m\]

    C)  5 N/m                                 

    D)  50 N/m

    Correct Answer: B

    Solution :

    Given,  \[r=2\times {{10}^{-3}}m.\] \[F=W=V\rho g=6.28\times {{10}^{-4}}m\] Surface tension \[(T)=\frac{F}{2\pi r}=\frac{6.28\times {{10}^{-4}}}{2\times 3.14\times 2\times {{10}^{-3}}}\]                                 \[=0.05N/m=5\times {{10}^{-2}}N/m\]


You need to login to perform this action.
You will be redirected in 3 sec spinner