A) \[\eta /2\]
B) \[\eta \]
C) \[2\eta \]
D) \[3\eta \]
Correct Answer: B
Solution :
Efficiency of heat engine, \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] when temperature of source and sink are doubled, then efficiency, \[\eta '=1-\frac{2{{T}_{2}}}{2{{T}_{1}}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\eta '=\eta \]
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