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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2006

  • question_answer
    The potential energy of a body is given by \[U=A-B{{x}^{2}}\] (where x is the displacement). The magnitude of force acting on the particle is                                 

    A)  constant

    B)  proportional to

    C)  proportional to x2                

    D)  proportional to 1/x

    Correct Answer: B

    Solution :

    Potential energy \[U=A-B{{x}^{2}}\] Force  \[F=-\frac{dU}{dx}\]                 \[=-(0-2Bx)\]                 \[F=2Bx\]                 \[\therefore \]                  \[F\propto x\]


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