A) \[20.13\]
B) \[2.013\]
C) \[2.198\]
D) \[21.98\]
Correct Answer: D
Solution :
\[\Delta {{S}_{fus}}=\frac{\Delta {{H}_{fus}}}{{{T}_{m}}}\] \[=\frac{6.0}{273}kJ\,{{K}^{-1}}\,mo{{l}^{-1}}\] \[\therefore \] \[\Delta {{S}_{fus}}=0.021978kJ\,{{K}^{-1}}\,mo{{l}^{-1}}\] \[1kJ\,=1000J\] \[\therefore \] \[\Delta {{S}_{fus}}=0.021978\times 1000\,\,J{{K}^{-1}}\,mo{{l}^{-1}}\] \[=21.978\,\,J{{K}^{-1}}\,mo{{l}^{-1}}\]
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