A) \[C{{r}^{4+}}\]
B) \[S{{c}^{3+}}\]
C) \[T{{i}^{3+}}\]
D) \[{{V}^{4+}}\]
Correct Answer: B
Solution :
d-d transition is responsible for colour of compound. For d-d transition ions have unpaired electrons in d-orbital. \[S{{c}^{3+}}\] has no electrons in d-orbital, so d-d transition is not possible, hence, \[S{{c}^{3+}}\] ion is colourless.
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