A) \[La{{(OH)}_{3}}\] is less basic than \[Lu{{(OH)}_{3}}\].
B) In lanthanide series ionic radius of \[L{{u}^{3+}}\] ion decreases.
C) \[La\] is actually an element of transition series rather lanthanide.
D) Atomic radius of \[Zr\] and Hf are same because of lanthanide contraction.
Correct Answer: A
Solution :
As the size of the lanthanide ions decreases from \[L{{a}^{3+}}\] to \[L{{u}^{3+}},\] the covalent character of the hydroxides increases and hence, the basic strength decreases. Thus, \[La{{(OH)}_{3}}\] is most basic whereas \[Lu{{(OH)}_{3}}\] is least basic.
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