A) primary alcohol
B) monocarboxylic acid
C) secondary alcohol
D) tertiary alcohol
Correct Answer: A
Solution :
Aldehyde on reduction gives primary alcohol, in this reaction number of carbon atoms in aldehyde and alcohol remain same. \[R-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-H\xrightarrow[2[H]]{LiAl{{H}_{4}}/ether}R-C{{H}_{2}}-OH\]
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