A) \[{{t}_{2}}:{{t}_{1}}\]
B) \[{{t}_{1}}:{{t}_{2}}\]
C) \[t_{2}^{2}:t_{1}^{2}\]
D) \[t_{1}^{2}:t_{2}^{2}\]
Correct Answer: A
Solution :
Heat transferred \[Q=\frac{KA\Delta \theta t}{l}\] Here A, \[\Delta \theta ,\] \[l\]and Q are same, therefore \[{{K}_{1}}{{t}_{1}}={{K}_{2}}{{t}_{2}}\] or \[\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{{{t}_{2}}}{{{t}_{1}}}\]
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