Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2007

  • question_answer
    The \[\text{v-t}\] graph of a moving object is given in figure. The maximum acceleration is

    A)  \[1\text{ }cm/{{s}^{2}}\]                             

    B)  \[\text{2 }cm/{{s}^{2}}\]

    C)  \[\text{3 }cm/{{s}^{2}}\]                             

    D) \[\text{6 }cm/{{s}^{2}}\]

    Correct Answer: D

    Solution :

    Slope of \[v-t\] graph represents acceleration. Sir of \[v-t\] graph is maximum during time interval \[30s\]to\[40s\]. \[\therefore \]Maximum acceleration \[=\frac{80-20}{40-30}=\frac{60}{10}\]                                                 \[=6cm/{{s}^{2}}\]


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