A) zero
B) \[{{10}^{-2}}N\]
C) \[{{10}^{-3}}N\]
D) \[{{10}^{-4}}N\]
Correct Answer: C
Solution :
Given \[I=10A,\]\[B={{10}^{-4}}T,\] \[l=1m\] Force acting on current carrying wire is \[F=BIl\sin \,\theta \] \[={{10}^{-4}}\times 10\times 1\times \sin \,{{90}^{o}}\] \[={{10}^{-3}}N\]You need to login to perform this action.
You will be redirected in
3 sec