A) 22 dyne
B) 20 N
C) 20 dyne
D) 100 N
Correct Answer: B
Solution :
The accelerating force on the rocket = upward thrust \[=\frac{\Delta m}{\Delta t}.u\] Given, \[=\frac{\Delta m}{\Delta t}=50\times {{10}^{-3}}kg/s,\] \[v=400m/s\] So, accelerating force \[=50\times {{10}^{-3}}\times 400\] \[=20N\]You need to login to perform this action.
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