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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    If \[{{g}_{E}}\] and \[{{g}_{M}}\] are the accelerations due  to gravity on the surfaces of the earth and  the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces,   one   will   find   the   ratio \[\frac{\text{electronic}\,\text{charge}\,\text{on}\,\text{the}\,\text{moon}}{\text{electronic}\,\text{charge}\,\text{on}\,\text{the}\,\text{earth}}\]to be

    A) \[1\]                                     

    B) \[\operatorname{zero}\]

    C) \[\frac{{{g}_{E}}}{{{g}_{M}}}\]                                   

    D) \[\frac{{{g}_{M}}}{{{g}_{E}}}\]

    Correct Answer: A

    Solution :

    According to Millikan's oil drop experiment, electronic charge is given by                 \[q=\frac{6\pi nr({{v}_{1}}+{{v}_{2}})}{E}\]which is independent of g. So,   \[\frac{electronic\text{ }charge\text{ }on\text{ }the\text{ }moon}{~electronic\text{ }charge\text{ }on\text{ }the\text{ }earth}=1\]


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