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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    In an oxidation-reduction reaction, \[MnO_{4}^{-}\] ion is converted to \[M{{n}^{2+}}\]What is the number of equivalents of \[KMn{{O}_{4}}\] \[(mol.\text{ }wt.=158)\]present in \[250\text{ }mL\]of \[0.04\text{ }M\]\[KMn{{O}_{4}}\] solution?

    A)  \[0.02\]                              

    B)  \[0.05\]

    C)  \[0.04\]                              

    D)  \[0.07\]

    Correct Answer: B

    Solution :

    Change in oxidation number \[=(+7)-(+2)=5\] \[\therefore \]  Normality of solution \[=5\times 0.04=0.20\text{ }N\] Volume \[=250mL\] \[\therefore \] Number of equivalents of \[KMn{{O}_{4}}\]                 \[=0.20\times \frac{250}{1000}=0.05\]


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