A) \[\frac{molecular\,weight}{3}\]
B) \[\frac{molecular\,weight}{6}\]
C) \[\frac{molecular\,weight}{1}\]
D) \[\frac{molecular\,weight}{2}\]
Correct Answer: B
Solution :
\[{{K}_{2}}\overset{+6}{\mathop{C{{r}_{2}}}}\,{{O}_{7}}+4{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}{{K}_{2}}S{{O}_{4}}+\overset{+3}{\mathop{C{{r}_{2}}}}\,{{(S{{O}_{4}})}_{3}}\] \[+4{{H}_{2}}O+3[O]\] Equivalent weight \[=\frac{Molecular\text{ }weight}{\begin{align} & Change\text{ }in\text{ }oxidation\text{ }number\text{ }of\text{ }atoms.~ \\ & present\text{ }in\text{ }one\text{ }molecule \\ \end{align}}\]\[\therefore \] Equivalent weight \[=\frac{Molecular\text{ }weight}{2\times 3}\] \[=\frac{Molecular\text{ }weight}{6}\]
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