Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2008

  • question_answer
    What is the wave number of 4th line in Bahner series of hydrogen spectrum? \[(R=1,09,677c{{m}^{-1}})\]

    A)  \[24,630\,c{{m}^{-1}}\]    

    B)  \[24,360\text{ }c{{m}^{-1}}\]

    C)  \[24,730\text{ }c{{m}^{-1}}~\]

    D)  \[24,372\text{ }c{{m}^{-1}}\]

    Correct Answer: D

    Solution :

    \[\overset{-}{\mathop{v}}\,=R\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] For Balmer series \[{{n}_{2}}=2\] and for 4th line in Balmer series \[{{n}_{2}}=6\] \[\because \]     \[R=109677\,c{{m}^{-1}}\]                 \[\overset{-}{\mathop{v}}\,=109677\left( \frac{1}{{{2}^{2}}}-\frac{1}{{{6}^{2}}} \right)\]                 \[=109677\left( \frac{1}{4}-\frac{1}{36} \right)\]                 \[\overset{-}{\mathop{v}}\,=\,24,372\,c{{m}^{-1}}\]


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