A) \[4\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[2\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[1\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[1.5\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: A
Solution :
Using the Bragg's formula \[2d\,\,\sin \theta =n\lambda \] waere d = distance between diffracting planes. We can determine the wavelength of these waves, \[2\times 4\times {{10}^{-10}}\,\sin \,{{30}^{o}}=\lambda \] \[8\times {{10}^{-10}}\times \frac{1}{2}=\lambda \] \[4\times {{10}^{-10}}=\lambda \] \[\lambda =4\overset{\text{o}}{\mathop{\text{A}}}\,\]
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