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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2009

  • question_answer
    If Young's modulus of elasticity Y for a material is one and half times its rigidity coefficient \[\eta \] the Poisson ratio \[\sigma \] will be

    A)  \[+\frac{2}{3}\]                               

    B) \[-\frac{1}{4}\]

    C) \[+\frac{1}{4}\]                                

    D) \[-\frac{2}{3}\]

    Correct Answer: B

    Solution :

    Young's modulus, \[Y=\frac{3\eta }{2}\] We know that \[Y=2\eta (1+\sigma )\]                 \[\therefore \]  \[\frac{3\eta }{2}=2\eta (1+\sigma )\]                 \[\Rightarrow \]               \[\sigma =-\frac{1}{4}\]


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