question_answer

The formula for horizontal range of a projectile is \[S=\frac{{{v}^{2}}\sin {{\,}^{2}}\text{ }\!\!\theta\!\!\text{ }}{2g}\] where v is initial speed, \[\text{ }\!\!\theta\!\!\text{ }\] angle of inclination and g is acceleration due to gravity. The Wheatstone bridge shown in figure can be used to determine the range if the following arrangement is made

A)                 Q proportional to v2 P proportional to g R proportional to \[{{\sin }^{2}}\text{ }\!\!\theta\!\!\text{ }\]

B)                 Q proportional to g P proportional to v2 R proportional to \[{{\sin }^{2}}\text{ }\!\!\theta\!\!\text{ }\]

C)                 Q proportional to g P proportional to \[{{\sin }^{2}}\text{ }\!\!\theta\!\!\text{ }\] R proportional to v2

D)                 Q proportional to \[{{\sin }^{2}}\text{ }\!\!\theta\!\!\text{ }\] P proportional to v2 R proportional to g