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Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2009

  • question_answer
    A current passing through a coil of self inductance of 2 mH changes at the rate of 20 mA s-1. The emf induced in the coil is

    A)  \[10\mu V\]                                     

    B)  \[40\mu V\]

    C)  10 mV                                 

    D)  40 mV

    Correct Answer: B

    Solution :

    By Faraday's second law, induced emf. \[e=-\frac{Nd\phi }{dt}\]  which gives \[e=-\frac{dI}{dt}\] \[\therefore \]  \[|e|=2\times {{10}^{-3}}\times 20\times {{10}^{-3}}V=40\mu V\]


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