A) \[Fe\]
B) \[{{O}_{2}}\]
C) \[{{H}^{+}}\]
D) \[Zn\]
Correct Answer: C
Solution :
The reactions occurring during rusting process are as follows At anode: \[Fe(s)\xrightarrow{{}}F{{e}^{2+}}(aq)+2{{e}^{-}}\] At cathode: \[{{O}_{2}}(g)+4{{H}^{+}}(aq)+4{{e}^{-}}\xrightarrow{{}}2{{H}_{2}}O\] The \[F{{e}^{2+}}\] ions, formed, are further oxidised by atmospheric oxygen to \[F{{e}^{3+}}\] (as \[F{{e}_{2}}{{O}_{3}}\]) and come out as rust \[(F{{e}_{2}}{{O}_{3}}.x{{H}_{2}}O)\]. The \[{{H}^{+}},\] formed in the rust formation, catalysed the process of rusting.
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