A) \[10\mu V\]
B) \[40\mu V\]
C) 10 mV
D) 40 mV
Correct Answer: B
Solution :
By Faraday's second law, induced emf. \[e=-\frac{Nd\phi }{dt}\] which gives \[e=-\frac{dI}{dt}\] \[\therefore \] \[|e|=2\times {{10}^{-3}}\times 20\times {{10}^{-3}}V=40\mu V\]You need to login to perform this action.
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