question_answer

Total number of lone pairs of electrons on \[Xe\]in \[XeO{{F}_{4}}\] is

A)  \[0\]                                    

B)  \[1\]

C)  \[2\]                                    

D)  \[3\]

Correct Answer: B

Solution :

Structure of \[XeO{{F}_{4}}\] is,