A) \[-329{}^\circ F\]
B) \[-261{}^\circ F\]
C) \[-215{}^\circ F\]
D) \[-297{}^\circ F\]
Correct Answer: D
Solution :
\[\frac{C}{5}=\frac{F-32}{9}\] \[\frac{-183}{5}=\frac{F-32}{9}\] \[F=-{{297}^{o}}F\]
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