Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2010

  • question_answer
    If the de-Broglie wavelength of the fourth Bohr's orbit of hydrogen atom is \[4\overset{\text{o}}{\mathop{\text{A}}}\,\] the circumference of the orbit is

    A)  \[4\overset{\text{o}}{\mathop{\text{A}}}\,\]                                  

    B)  \[4nm\]

    C)  \[16\overset{\text{o}}{\mathop{\text{A}}}\,\]                                

    D)  \[16\text{ }nm\]

    Correct Answer: C

    Solution :

    de-Broglie wavelength, \[\lambda =\frac{2\pi {{r}_{n}}}{n}\] \[\therefore \]  The circumference of the orbit,                 \[2\pi {{r}_{n}}=\lambda \times n=4\times 4=16\overset{\text{o}}{\mathop{\text{A}}}\,\]


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