A) 28MHz
B) 280MHz
C) 2.8 GHz
D) 28 GHz
Correct Answer: D
Solution :
Cyclotron frequency \[v=\frac{Bq}{2\pi m}\] \[=\frac{1\times 1.6\times {{10}^{-19}}}{2\pi \times 9.1\times {{10}^{-31}}}\] \[=2.8\times {{0}^{10}}Hz\] \[=28GHz\]
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