Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2011

  • question_answer
    A proton moving with velocity v is acted upon by electric field E and magnetic field B. The proton will move undetected, if

    A)  E is perpendicular to B

    B)  E is parallel to v and perpendicular to B

    C)  E, B and v are mutually perpendicular and \[v=\frac{E}{B}\]

    D)  E and B both are parallel to v

    Correct Answer: C

    Solution :

    If magnetic field B, and electric field E are perpendicular to the direction of motion of proton, then proton will move without any  deflection. So, magnetic force = electric force.                 \[evB=eE\] \[\therefore \]  \[v=\frac{E}{B}\] \[\therefore \]E, B and v are mutually perpendicular and          \[v=E/B\]


You need to login to perform this action.
You will be redirected in 3 sec spinner