2. Solved Papers
  3. Chhattisgarh PMT

Chhattisgarh PMT Chhattisgarh PMT Solved Paper-2011

  • question_answer
    Three masses\[{{m}_{1}},{{m}_{2}},{{m}_{3}}\] are joined from weightless string and are kept on frictionless table. They are pulled by a force \[{{T}_{3}}\] of 40 N. If \[{{\text{m}}_{\text{1}}}\text{=10}\,\text{kg,}\]\[{{\text{m}}_{2}}\text{=6}\,\text{kg,}\,\]\[{{\text{m}}_{3}}\text{=}\,\text{4}\,\text{kg,}\,\] Then, value of \[{{T}_{2}}\] will be

    A)  20 N                                     

    B)  40 N

    C)  10N                                      

    D)  32 N

    Correct Answer: D

    Solution :

    Acceleration of the system \[a=\frac{{{T}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}\] \[=\frac{40}{10+6+4}=2m/{{s}^{2}}\] Tension in the string \[{{T}_{2}}=({{m}_{1}}+{{m}_{2}})a\]                                                 \[=(10+6)\times 2\]                                                 \[=32N\]


You need to login to perform this action.
You will be redirected in 3 sec spinner