A) \[-1\] and \[+5\]
B) \[+1\] and \[+4\]
C) \[+5\] and \[+3\]
D) \[-1\] and \[+1\]
Correct Answer: D
Solution :
When chlorine reacts with dilute and cold \[NaOH,\]sodium chloride and sodium hypochloride are formed. \[2NaOH\,(cold)+C{{l}_{2}}\]\[\xrightarrow{{}}NaCl+\underset{hypochloride}{\mathop{\underset{sodium}{\mathop{NaClO}}\,}}\,+{{H}_{2}}O\] Let oxidation state of \[Cl\]in \[NaCl\]is x. \[NaCl\] \[+1+x=0\] \[x=-1\] Let oxidation state of \[Cl\] in \[NaClO\]is x. \[NaClO\] \[1+x-2=0\] \[x-1=0\] \[x=+1\] \[\therefore \]Oxidation states of chlorine changes from 0 to \[-1\] and \[+1\].
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