question_answer

A ground \[100\times 80\,\,{{\text{m}}^{\text{2}}}\] has, two cross roads in its middle. The road parallel to the length is 5 m wide and the other road is 4 m wide, both roads are perpendicular to each other. The cost of laying the bricks at the rate of Rs 10 per m2, on the roads, will be

A)  Rs 700                       

B)  Rs 8000

C)  Rs 900                       

D)  Rs s1000

Correct Answer: B

Solution :

Ans.  \[\therefore \] Area to be paved with bricks\[=5\times 100+4\times 80-4\times 5\] \[={{800}^{2}}\] So, cost of lying bricks \[=800\times 10=\text{Rs}\,\,\text{8000}\]