A) \[\frac{35}{367},\,\frac{30}{313}\,,\,\frac{42}{491}\]
B) \[\frac{42}{491},\,\frac{35}{367}\,,\,\frac{30}{313}\]
C) \[\frac{30}{313},\,\frac{35}{367}\,,\,\frac{42}{491}\]
D) \[\frac{42}{491},\,\frac{30}{313}\,,\,\frac{35}{367}\]
Correct Answer: B
Solution :
| Sol. |
| \[\frac{42}{491}\,=\,0.085539\] |
| \[\frac{30}{313}\,=\,0.095846\Rightarrow \frac{35}{367}\,=\,0.095367\] |
| \[0.085539<0.095367<0.095846\] |
| Clearly, \[\frac{42}{491}\,<\,\frac{35}{367}\,<\frac{30}{313}\] |
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