A) 9: 30 am
B) 10:00 am
C) 10:30 am
D) 11:00 am
Correct Answer: D
Solution :
| Sol. [d] |
| Pipe A can filled the tank in \[1\,h\,=\frac{1}{15}\] |
| Pipe B can filled the tank in \[1\,h\,=\frac{1}{20}\] |
| Pipe C can filled the tank in \[1\,h\,=\frac{1}{30}\] |
| and pipe D can filled the tank in \[1\,h\,=\frac{1}{60}\] |
| Pipe A filled the water in \[3\,h\,=\,\frac{3}{15}\,=\frac{1}{5}\] |
| Pipe B filled the water in \[2\,h\,=\,\frac{2}{20}\,=\frac{1}{10}\] |
| Pipe C filled the water in \[1\,hours\,=\,\frac{1}{30}\] |
| Total water filled till 7 am |
| \[=\,\frac{1}{5}\,+\frac{1}{10}\,+\frac{1}{30}\,=\,\frac{6+3+1}{30}\] |
| \[=\,\frac{10}{30}\,=\frac{1}{3}\] |
| So, remaining tank will fill by all four pipes together |
| \[\therefore \,\frac{2}{3}\,rd\] of pipe filled in \[=\,\frac{2}{3}\,\times \,6\,=\,4\,h\] |
| \[\therefore \]Required time = 7 am + 4h = 11 am |
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