CLAT CLAT Solved Paper-2018

  • question_answer
    \[{{x}^{2}}\,(a-b)+{{a}^{2}}(b-x)+({{b}^{2}}(x-a)\] is factored as

    A) (a - b) (x - a) (x - b)

    B) (a - b) (x - a) (x + b)

    C) (b - a) (x + a) (x - b)

    D) (a + b) (x - a) (x + b)

    Correct Answer: A

    Solution :

    Sol.      [a]
    By checking all options
    (a - b) (x - a) (x - b) is the factor.
    \[\Rightarrow \,(a-b)(x-a)(x-b)\]
    \[=\,(ax-{{a}^{2}}-bx+ab)\,(x-b)\]
    \[=\,\,a{{x}^{2}}\,-{{a}^{2}}x\,-b{{x}^{2}}+abx-abx\]
    \[+\,{{a}^{2}}b\,+{{b}^{2}}x-a{{b}^{2}}\]
    \[=\,{{x}^{2}}\,(a-b)\,+{{b}^{2}}\,(x-a)\,+{{a}^{2}}(b-x)\]
    Hence, option is correct answer.


You need to login to perform this action.
You will be redirected in 3 sec spinner