2. Solved Papers
  3. CLAT

CLAT CLAT Solved Paper-2019

  • question_answer
    Beena got married 8 yr ago. Today, her age \[1\frac{1}{4}\]times her age at the time of marriage. If her daughter's age is 1/10 times her age, then her daughter's age is

    A) 3yr                               

    B) 4yr   

    C) 5yr                               

    D) 2yr

    Correct Answer: B

    Solution :

    Sol.      [b] Let the present age of Beena is x yr. \[\therefore \]Beena's age at the time other marriage = (x - 8) yr \[\therefore \,\,\,\,\,x=1\frac{1}{4}\,of\,(x-8)\,\Rightarrow x=\,\frac{5}{4}\,(x-8)\] \[\Rightarrow \,4x=\,5x\,-\,40\] \[\therefore \,\,x=40yr\] Now Beena's daughter's age\[=\,\frac{1}{10}\,\times \,40\,=\,4yr\]


You need to login to perform this action.
You will be redirected in 3 sec spinner