A) 30 km/min
B) 60 km/min
C) 30 m/s
D) 500 m/s
Correct Answer: D
Solution :
Conservation of linear momentum gives, \[{{m}_{1}}{{v}_{1}}+{{m}_{2}}{{v}_{2}}=0\] \[{{m}_{1}}{{v}_{1}}=-\,{{m}_{2}}{{v}_{2}}\] \[{{v}_{1}}=\frac{-{{m}_{2}}{{v}_{2}}}{{{m}_{1}}}\] Given : \[{{m}_{1}}=10g=\left( \frac{10}{1000} \right)\,kg,\,{{m}_{2}}=1\,kg,\] \[{{v}_{2}}=-\,5\,m\text{/}s\] \[\therefore \] \[{{v}_{1}}=\frac{1\times 5}{10/1000}\] or \[{{v}_{1}}=500\,m\text{/}s\]
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