A) Fe
B) Ag
C) Al
D) Cu
Correct Answer: D
Solution :
In a bessemer converter, copper pyrites are oxidised to \[FeO\]and\[C{{u}_{2}}O\]. \[FeO\] is slagged off. \[C{{u}_{2}}O\] reacts with \[C{{u}_{2}}S\]left unoxidised to give \[Cu.\] \[3C{{u}_{2}}S+3{{O}_{2}}\xrightarrow{{}}2C{{u}_{2}}+2S{{O}_{2}}\uparrow \]\[2C{{u}_{2}}O+C{{u}_{2}}S\xrightarrow{{}}6Cu+S{{O}_{2}}\uparrow \]
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