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CMC Medical CMC-Medical Ludhiana Solved Paper-2008

  • question_answer
    A inductive coil has a resistance of 100\[\Omega \]. When an AC signal of frequency 1000 Hz is applied to the coil, the voltage leads the current by\[45{}^\circ \]. The inductance of the coil is

    A)  \[\frac{1}{10\pi }\]                         

    B)  \[\frac{1}{20\pi }\]

    C)  \[\frac{1}{40\pi }\]                         

    D)  \[\frac{1}{60\pi }\]

    Correct Answer: B

    Solution :

                                    \[\tan \phi =\frac{{{X}_{L}}}{R}\] \[\Rightarrow \]               \[\tan 45{}^\circ =\frac{L\omega }{R}\] \[\Rightarrow \]               \[L=\frac{R}{\omega }=\frac{100}{2\pi (1000)}\] \[[\because \,tan\,45{}^\circ =1]\] \[\Rightarrow \]               \[L=\frac{1}{20\,\pi }\]


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