A) + 2
B) + 4
C) + 6
D) + 7
Correct Answer: C
Solution :
The chemical structure of \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\] is as follows : \[H-O-\underset{O}{\overset{O}{\mathop{\underset{\mathbf{||}}{\overset{\mathbf{||}}{\mathop{S}}}\,}}}\,-O-O-\underset{O}{\overset{O}{\mathop{\underset{\mathbf{||}}{\overset{\mathbf{||}}{\mathop{S}}}\,}}}\,-O-H\] Let the oxidation number of S is x. \[\begin{matrix} \,\,\,\,2\times (+1) & +2\times x & +6\times (-2) & +2\times (-1) \\ \text{For}\,\text{H} & \text{for}\,\,\text{S} & \text{for}\,\,\text{O} & \text{for}\,\text{(O}-\text{O)} \\ \end{matrix}\] \[2+2x-12-2=0\] \[2x=12\] \[x=+6\]
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