A) Only symmetrical ethers
B) Only asymmetrical ethers
C) Both (a) and (b)
D) None of the above
Correct Answer: C
Solution :
For synthesis of symmetrical ethers: \[C{{H}_{3}}{{O}^{-}}N{{a}^{+}}+BrC{{H}_{3}}\xrightarrow{{}}\underset{\begin{smallmatrix} \text{ dimethyl}\,\,\text{ether} \\ \text{(symmetrical}\,\text{ether)} \end{smallmatrix}}{\mathop{C{{H}_{3}}OC{{H}_{3}}+NaBr}}\,\] For synthesis of asymmetrical ethers: \[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\overset{\mathbf{|}}{\mathop{C}}}\,}}}\,-{{O}^{-}}N{{a}^{+}}+C{{H}_{3}}Br\] \[\xrightarrow{{}}\underset{\begin{smallmatrix} \text{methyl}\,\text{ter-butyl}\,\text{ether} \\ \text{(asymmetrical}\,\text{ether)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{\mathbf{|}}{\overset{\mathbf{|}}{\mathop{C}}}\,}}}\,-O-C{{H}_{3}}+NaBr}}\,\]
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