A) 0.98 T
B) 1.02 T
C) 0.99 T
D) 1.01 T
Correct Answer: D
Solution :
\[T\propto {{l}^{1/2}}\] \[\Rightarrow \] \[\frac{\Delta T}{T}=\frac{1}{2}\left( \frac{\Delta l}{l} \right)\] \[\frac{\Delta T}{T}=\frac{1}{2}(2%)=1%\] \[\Rightarrow \] \[\frac{T-T}{T}=\frac{1}{100}\] \[\Rightarrow \] \[T=T+0.01\,T\] \[\Rightarrow \] \[T=0.01\,T\]
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