A) \[1\text{/}100\,cm\]
B) \[6.6\times {{10}^{-34}}m\]
C) \[1.32\times {{10}^{-35}}m\]
D) \[6.6\times {{10}^{-28}}m\]
Correct Answer: C
Solution :
From de-Broglie equation \[\lambda =\frac{h}{mv}\] \[=\frac{6.62\times {{10}^{-34}}}{0.5\times 100}=1.32\times {{10}^{-35}}m\]
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