CMC Medical CMC-Medical Ludhiana Solved Paper-2008

  • question_answer
    Ethyl alcohol is heated with cone \[{{H}_{2}}S{{O}_{4}}.\] The product formed is

    A)  \[C{{H}_{3}}-\overset{O}{\mathop{\overset{\mathbf{||}}{\mathop{C}}\,}}\,-O{{C}_{2}}{{H}_{5}}\]       

    B)  \[{{C}_{2}}{{H}_{6}}\]

    C)  \[{{C}_{2}}{{H}_{4}}\]                   

    D)  \[{{C}_{2}}{{H}_{2}}\]

    Correct Answer: C

    Solution :

                    Ethyl alcohol on dehydration with cone \[{{H}_{2}}S{{O}_{4}}\] at \[170{}^\circ C,\]gives ethylene. \[C{{H}_{3}}C{{H}_{2}}OH\xrightarrow[conc.\,{{H}_{2}}S{{O}_{4}}]{170{}^\circ C}\underset{\text{ethylene}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,+{{H}_{2}}O\]


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