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CMC Medical CMC-Medical Ludhiana Solved Paper-2009

  • question_answer
    A wire PQR is bent as shown in figure and is placed in a region of uniform magnetic field B. The length of PQ = QR = I. A current I ampere flows through the wire as shown. The magnitude of the force on PQ and QR will be

    A)  BIl, 0                                    

    B)  2BIl, 0

    C)  0, BIl                                    

    D)  0, 0

    Correct Answer: C

    Solution :

                    The Lorentz force acting on the current carrying conductor in the magnetic field is \[F=IBl\,\sin \theta \] Since, wire PQ is parallel to the direction of magnetic field, then \[\theta =0,\] \[\therefore \]  \[{{F}_{PQ}}=IBl\,\sin 0{}^\circ =0\] Also, wire QR is perpendicular to the direction of magnetic field, then\[\theta =90{}^\circ .\] \[\therefore \]  \[{{F}_{QR}}=IBl\,\sin 90{}^\circ =IBl\]


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