A) \[5\times {{10}^{-10}}N\]
B) \[4\times {{10}^{-10}}N\]
C) \[2\times {{10}^{-5}}N\]
D) \[9\times {{10}^{-4}}N\]
Correct Answer: A
Solution :
\[[{{H}^{+}}]\,[O{{H}^{-}}]={{K}_{w}}\] \[2\times {{10}^{-5}}\times [O{{H}^{-}}]=1\times {{10}^{-14}}\] \[[O{{H}^{-}}]=\frac{1\times {{10}^{-14}}}{2\times {{10}^{-5}}}\] \[=0.5\times {{10}^{-9}}\] \[=5\times {{10}^{-10}}\]
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