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CMC Medical CMC-Medical Ludhiana Solved Paper-2009

  • question_answer
    In the conversion of\[B{{r}_{2}}\]to\[BrO_{3}^{-},\]the oxidation number of Br changes from

    A)  zero to \[+\,5\]                               

    B)  + 1 to + 5

    C)  zero to \[-\,3\]                

    D)  + 2 to + 5

    Correct Answer: A

    Solution :

                    Bromine has zero oxidation state because it is in free state \[\overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow{{}}BrO_{3}^{-}\] \[BrO_{3}^{-}\] \[x+(-2\times 3)=-1\] \[x+(-\,6)=-1\] \[x=+\,6-1\] \[=+\,5\] So, oxidation number changes from 0 to + 5.


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