A) \[1.73\times {{10}^{-4}}\text{ }M\text{ mi}{{\text{n}}^{-1}}\]
B) \[3.47\times {{10}^{-4}}\text{ }M\text{ mi}{{\text{n}}^{-1}}\]
C) \[3.47\times {{10}^{-5}}\text{ }M\text{ mi}{{\text{n}}^{-1}}\]
D) \[7.5\times {{10}^{-4}}\text{ }M\text{ mi}{{\text{n}}^{-1}}\]
Correct Answer: D
Solution :
\[k=\frac{2.303}{t}\log \frac{{{A}_{0}}}{A}\] \[=\frac{2.303}{40}\log \frac{0.1}{0.005}\] \[=\frac{2.303}{40}\log \,\,20=0.075\] Rate of reaction when concentration of X is 0.01 M will be \[=0.075\times 0.01=7.5\times {{10}^{-4}}M\text{ mi}{{\text{n}}^{-1}}\]
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